18x^2-72-96x=0

Solution for 18x^2-72-96x=0 equation:

18x^2-72-96x=0

a = 18; b = -96; c = -72;
Δ = b2-4ac
Δ = -962-4·18·(-72)
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14400}=120$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-96)-120}{2*18}=\frac{-24}{36}
=-2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-96)+120}{2*18}=\frac{216}{36}
=6
$